ABCD IS A RHOMBUS SUCH THAT ANGLE ACB=50 FIND ANGLE ADB
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If this is proportional so we can use tan/ sin... and theeta . and if it is proportional so the angle will will same 50 degemrees
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Angle ACB =50°
since diagonals of rhombus are perpendicular to each other.
=> angle AOD=90°
Also angle DAC=50° .... (ALTERNATE ANGLES)
Now in ∆AOD
<A+<O+<D=180°
50+90+<ADB=180°
<ADB=180-140
<ADB=40°
since diagonals of rhombus are perpendicular to each other.
=> angle AOD=90°
Also angle DAC=50° .... (ALTERNATE ANGLES)
Now in ∆AOD
<A+<O+<D=180°
50+90+<ADB=180°
<ADB=180-140
<ADB=40°
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chopraneetu:
mark it as brainliest
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