Abcd is a rhombus whose diagonal ac makes an angle alpha with ab. if cos alpha is 2/3 and ob =3cm, find the length of its diagonals ac and bd?/
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Cos alpha = 2/3
Sin alpha = 1 - 2/3
= 1/3
Thus tan alpha = 1/2
Thus
1/2 = BO / AO
1/2 = 3/AO
AO = 6 Cm
Thus AC= 12 Cm
and BD = 6 Cm
Sin alpha = 1 - 2/3
= 1/3
Thus tan alpha = 1/2
Thus
1/2 = BO / AO
1/2 = 3/AO
AO = 6 Cm
Thus AC= 12 Cm
and BD = 6 Cm
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