ABCD is a rhombus whose diagonal AC makes an angle Alpha with a b if cos alpha is equal to 2 upon 3 and OB is equal to 3 cm find the length of AC and BD
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Let the diagonals AC and BD intersect each other at O
Thus according to question
Angle BAO = Angle alpha
and
Cos Alpha = 2/3
Thus in triangle AOB
Cos alpha = AO / AB
and Sin alpha = OB/AB
1/3 = 3/AB
Thus AB = 9
SO tan alpha = OB/AO
1/2 = 3/AO
AO = 6
Thus AC= 12
and BD = 6
Thus according to question
Angle BAO = Angle alpha
and
Cos Alpha = 2/3
Thus in triangle AOB
Cos alpha = AO / AB
and Sin alpha = OB/AB
1/3 = 3/AB
Thus AB = 9
SO tan alpha = OB/AO
1/2 = 3/AO
AO = 6
Thus AC= 12
and BD = 6
salma20:
thanks a lot
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