Question

ABCD is a rhombus whose diagonal intersect at O. If AB equal 10cm diagonal BD equal 16 cm,find the length of diagonal AC

Answer 1

$\bold{\boxed{Hoi!}}$

Let the point if intersection of diagonals be O.

We know that diagonals of rhombus $\textbf{bisect}$ each other at 90°

Then, BO=OD=16/2=8cm

Now, in ∆ AOB,

AB²=OB²+AO²
=> AO²= AB²-AO²
=> AO²= 10²-8²=36=6²
=> AO=6cm

Therefore, AC= 2AO= 2×6= 12cm

$\bold{\underline{Thanks!}}$☺️...

Answer 2

❤❤Here is your answer ✌ ✌

$\huge\underline {\red {\bold {Answer}}}$


given:-

ABCD is a rhombus
AB =10cm
diagonal BD=16 cm

Let
The point if intersection of diagonals be O.

➡We know that diagonals of rhombus bisect each other at 90°

Then, BO=OD=16/2=8cm

Now, in ∆ AOB,

AB²=OB²+AO²{using pythagoream theorem}
=> AO²= AB²-AO²
=> AO²= 10²-8²=36=6²
=> AO=6cm

Therefore, AC= 2AO= 2×6= 12cm ↩