Abcd is a rhombus whose diagonals ac and bd intersect at a point o. If side ab=10cm and diagonal bd=16cm, find the length of diagonal ac
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Answer:
12 cm
Step-by-step explanation:
In a rhombus, all the sides are equal and diagonals bisect each other at 90°. Since diagonals bisect each other, AO=OC and DO=OB=8cm. By Pythagoras theory:
AO^2+OB^2=AB^2
AO^2+8^2=10^2
AO^2+64=100
AO^2=100-64
AO^2=36
AO=square root of 36=6cm
Since AO=OC
therefore, OC=6cm
And hence, AC=6+6=12cm
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