Abcd is a rhombus whose diagonals ac makes an angle a with ab.if cos a=2/3 and ob=3cm.find the length of the diagonal ac and bd.
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Given that
OB = 3 Cm
and Cos BAC = 2/3
Now in traingle AOB
SInce it is a right angle triangle
Cos BAC = 2/3
Sin BAC = 1-2/3
Sin BAC = 1/3
OB/AB = 1/3
Thus
AB = 9
also tan BAC = 1/2
OB/AO = 1/2
Thus AO = 6 Cm
Thus lenght of AC = 3*2 = 6 Cm
and BD = 6*2 = 12 Cm
OB = 3 Cm
and Cos BAC = 2/3
Now in traingle AOB
SInce it is a right angle triangle
Cos BAC = 2/3
Sin BAC = 1-2/3
Sin BAC = 1/3
OB/AB = 1/3
Thus
AB = 9
also tan BAC = 1/2
OB/AO = 1/2
Thus AO = 6 Cm
Thus lenght of AC = 3*2 = 6 Cm
and BD = 6*2 = 12 Cm
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