Question

ABCD is a rhombus with angle ABC =56 degree . Determine Angle CAD​

Answer 1

Answer:

∠BOA = 90º (vertically opposite angle)

∠BA0 = 180 - 56 - 90 = 34º (Sum of angles in a triangle)

∠BCA = 56º (Isosceles triangle)

∠BAC = 180 - 56 - 56 = 68º (Sum of angles in a triangle)

∠CAB = ∠BAC - ∠BAO

∠CAB = 68 - 34 = 34º

Answer: ∠CAB = 34º

Answer 2

Answer:

CAD=34°

Step-by-step explanation:

Angle CAD will be 34. Because in rhombus opposite angles are equal. Let angle CAD be x. Then the some of its opposite angle and the angle be 2x. Now,

2*56+2x=180°

112°+2x=180°

2x=180°-112°

=68°

x=34°

So angle CAD=34°