Math, asked by FAZALBAKHSH, 11 months ago

ABCD is a rhombus with angle abc equal to 40 degree the measure of angle ACD is

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Answered by Vandan2080
54
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Answered by yapuramvaishnavi16
0

ABCD is a rhombus with angle ABC equal to 40 degree the angle of ACD is 70°.

Given that,

ABCD is a rhombus with angle ABC equal to 40°.

We have to find the angle of ACD is.

We know that,

In the picture we can see the rhombus ABCD.

The angle ABC is 40°

So,

In rhombus is also a parallelogram in parallelogram opposite sides are equal so angle ABC is equal to ADC

∠ADC = 40°

From the Adjacent angles

∠ABC + ∠BCD = 180°

40° + ∠BCD = 180°

∠BCD = 180°-40°

∠BCD = 140°

Now, AC is bisecting the C because the diagonal of rhombus bisect angle so.

∠ACD is 70°

Therefore, ABCD is a rhombus with angle ABC equal to 40° the angle of ACD is 70°.

To learn more about rhombus visit:

https://brainly.in/question/1239543

https://brainly.in/question/3527512

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