ABCD is a rhombus with angle abc equal to 40 degree the measure of angle ACD is
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ABCD is a rhombus with angle ABC equal to 40 degree the angle of ACD is 70°.
Given that,
ABCD is a rhombus with angle ABC equal to 40°.
We have to find the angle of ACD is.
We know that,
In the picture we can see the rhombus ABCD.
The angle ABC is 40°
So,
In rhombus is also a parallelogram in parallelogram opposite sides are equal so angle ABC is equal to ADC
∠ADC = 40°
From the Adjacent angles
∠ABC + ∠BCD = 180°
40° + ∠BCD = 180°
∠BCD = 180°-40°
∠BCD = 140°
Now, AC is bisecting the C because the diagonal of rhombus bisect angle so.
∠ACD is 70°
Therefore, ABCD is a rhombus with angle ABC equal to 40° the angle of ACD is 70°.
To learn more about rhombus visit:
https://brainly.in/question/1239543
https://brainly.in/question/3527512
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