ABCD is a Rhombus with angle ABC is 56 degree .Find the angle cad
yash9272:
wrong answer
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Answer:
∠BCD
= 180° - ∠ABC
= 180° - 56°
= 124°
Diagonals of a rhombus bisect the interior angles.
∠ACD
= ∠BCD/2
= 124°/2
= 62°
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