Math, asked by vishnupatil67, 1 year ago

ABCD is a rhombus with angle DAC=50 find angle ACD,CAB AND ABC.

Answers

Answered by Mahira13
27
angle ACD=50 =angleDAC( angles opposite to equal side are equal). angle CAB=50=ACD(AIA). In triangle ABC Angle BAC=50=ACD(AIA). Angles BAC+angle ACB+angleABC=180. 50+50+angle ABC=180. 100+ABC=180. ABC=180-100=80 BC=80
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