find the number of moles in 19g of AL2(CO3).(atomic mass unit Al =27 u, H = 1u, O=16 u and C = 12 u).
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Al2(CO3)=27*2+(40+16*3)
54+88
=142u
19/142=find the answerr
54+88
=142u
19/142=find the answerr
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