Question

ABCD is a rombus such that angle ABC=40degree then angle ADB is​

Answer 1

Answer:

20 degree

Step-by-step explanation:

∆ ABC =40 Degree , diagonal ADB = 20 degree

Answer 2

in rhombus ABCD,

angle ACB = angle CAD = 40. (. alt int. angle )

now,

angle AOD = 90 ( diagonal of rhombus bisect each other at 90 degree)

so, in triangle AOD ,

angle COD + angle AOD +angle ODA = 180

40 + 90 + ADB = 180

ADB = 180 - 130= 50

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