abcd is a sq. with one vertex at the center of the circle and two vertices on the circle what is the length of ac if the area of circle is 616 cm2
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=>. ABCD is a square with one corner in the center of the circle and two other corners on the circle’s edge. This makes each side of the square equivalent in length to the radius of the circle. AC is opposite corners of the square, so you want the diagonal of the square.
Through the Pythagorean theorem, we know that the diagonal of the square is sqrt2sqrt2 times the length of each side.
So — now find the circle’s radius. Area of a circle is pi∗r2pi∗r2 , so :
A=pi∗r2A=pi∗r2
616cm2/pi=r2616cm2/pi=r2
r=sqrt(616cm2/3.14159)r=sqrt(616cm2/3.14159)
AC=sqrt(2)∗rAC=sqrt(2)∗r
AC=sqrt(1232cm2/3.14159)
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=>. ABCD is a square with one corner in the center of the circle and two other corners on the circle’s edge. This makes each side of the square equivalent in length to the radius of the circle. AC is opposite corners of the square, so you want the diagonal of the square.
Through the Pythagorean theorem, we know that the diagonal of the square is sqrt2sqrt2 times the length of each side.
So — now find the circle’s radius. Area of a circle is pi∗r2pi∗r2 , so :
A=pi∗r2A=pi∗r2
616cm2/pi=r2616cm2/pi=r2
r=sqrt(616cm2/3.14159)r=sqrt(616cm2/3.14159)
AC=sqrt(2)∗rAC=sqrt(2)∗r
AC=sqrt(1232cm2/3.14159)
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