ABCD is a square 3 masses 2M, 4M & M are placed at 3 vertices at A,B& C respectively. Find the value of mass placed at D. Such that centre of mass of the system is at origin
Answers
Answered by
1
Answer:
ajajahahshshshsbababababb
Explanation:
7
0.25
×49
0.075
×343
0.2
243
0.13
×243
0.07
=(
3
7
)
2x
243canbewrittenas243=3
5
49=7
2
and343=7
3
7
0.25
×(7
2
)
0.075
×(7
3
)
0.2
(3
5
)
0.13
×(3
5
)
0.07
=(
3
7
)
2x
weknowthat
a
m
×a
n
=a
(m+n)
and(a
m
)
n
=a
mn
7
(0.25+0.150+0.6)
3
(0.65+0.35)
=(
3
7
)
2x
7
1.0
3
1.00
=(
3
7
)
2x
7
3
=(
3
7
)
2x
(
3
7
)
−1
=(
3
7
)
2x
sincea
−n
=
a
n
1
weknowthat
ifbasesareequalthenexponentsmustbeequal
=>−1=2x
=>x=
2
−1
Answered by
0
Answer:
-5/2 hai mitra iska answer according to me pakka nahi pata mujhe
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