sum of certain sum of certain consecutive odd numbers starting from 1 is 324 how many odd numbers are added
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Here ;
sum of consecutive odd numbers = (S) = 324
first term = a = (t1) = 1
difference between two consecutive odd numbers = (d) = 5-3 = 3-1 = 2
no. of odd numbers added = n
Formula for a sum of consecutive odd numbers =
2S = n*[ 2a + (n-1)d]
2*(324) = n*[2*(1) + (n-1)*2 ]
628 = n* [2*(1)+ (n-1)*2]
628 = n* [2 (1+n-1)] ....(Taking 2 common in RHS)
628 = n*2*(n)
628 = 2n²
Divide both sides by 2
324 = n²
Taking Square-root both sides
18 = n
i.e. n = 18
Therefore 18 odd numbers are added for getting sum 324.
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