Question

ABCD is a square.A line segment CX cuts AB at X and the diagonal BD at O, such that angle COD=80° and angle OXA=x° . Find the value of x°

Answer 1

Answer:

Step-by-step explanation:

=> According to the question, ABCD is a square. and a line segment CX cuts AB at X and the diagonal BD at O, such that ∠COD=80°.

But, diagonal of a square also bisects their angles.

∴ ∠ADB = ∠ABD = 45°

=> Here, ∠COD and ∠XOD are supplementary angles.

∴ ∠COD + ∠XOD = 180°

80° + ∠XOD = 180°    [ ∵ ∠COD = 80°]

∠XOD = 180° - 80°

∠XOD = 100°

=> Suppose, AXOD is the quadrilateral. so the sum of its angles is:

∠AXO + ∠XOD + ∠ADO + ∠XAD = 360°

x + 100° + 45° + 90° = 360°

x + 235° = 360°

x = 360° - 235°

x = 125°

Therefore, the value of x is 125°.

Answer 2

Answer:

Step-by-step explanation: