Question

ABCD is a square and AC is one of its diagonals.
Prove that triangle ABC = triangle CDA.
Hint: Use SSS congruence criterion to prove triangle ABC = triangle CDA]​

Answer 1

Answer:

Step-by-step explanation:

In ΔABC and ΔACD

AB = CD    {Sides of square}

BC = AD    {Sides of square}

AC = AC    {Common Side}

By SSS concurrence criteria,

ar(ΔABC) = ar(ΔACD)