ABCD IS A SQUARE AND EF PARALLEL TO BD .PROVE THAT BE=DF
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In triFEB AND triFED
FE=FE
AngleBEF=AngelDBE
ANGLE(DBE)=ANGLE(BEF)
Therefore triangle congruent by aas rule
Therefore DF=BF(CPCT)
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FE=FE
AngleBEF=AngelDBE
ANGLE(DBE)=ANGLE(BEF)
Therefore triangle congruent by aas rule
Therefore DF=BF(CPCT)
Hope this helps click on the thanks button
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