ABCD is a square and from D and C two quadrants find area of circle
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Answer:
Area of square ABCD=side×side
=(a×9) cm
2
=81 cm
2
Area of 2 quadrant=2×(
4
1
πr
2
)
=(2×
4
1
×
7
22
×9×9)
⇒
7
81×11
=
7
891
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