Question

ABCD is a square and on the side DC an equilateral triangle is constructed prove that AE is equal to BE and angle DAE is equal to 15 degree

Answer 1

In triangle ADE and BCE ,
Eq. 1 :
angleADC = angle BCD = 90°
angle EDC = angle ECD as triangle ECD is an equilateral triangle.
so angle EDA = angle ECB

AD = BC ( same sides of a square )
DE = CE ( equal sides of an equilateral triangle)
angle EDA = angle ECB
By SAS both are congruent. .....
By CPCT , AE = BE .....
Don't have idea for second part sorry

Answer 2

I think it is right mark me as branlist