Question

abcd is a square boc is an equilateral triangle where the point O is outside the square. then the value of angle aod will be​

Answer 1

Answer:

Solution

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ΔOAB is equilateral triangle then

ln ΔAOD and ΔBOC

AD=BC (sides of the square)

∠DAO=∠CBD=30

0

(90

0

−angleofequilateralΔ(60

0

))

AO=OB (sides of equilateral of triangle)

ΔAOD≅ΔBOC (SAS criterion)

then OD=OC

So ΔCOD is an isosceles triangle

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