Solve
с
D
1) ABCD is a cyclic quadrilateral in which AB is parallel
B
to DC and AB is a diameter of the circle.
A
Given ZBED = 65°;
E
[3]
calculate: (i) ZDAB (ii) ZBDC
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1
Answer:
∠DAB = ∠BED = 65°
(Angle subtended by the same chord on the circle are equal)
(ii) ∠ADB = 90°
(Angle in a semicircle is a right angle)
∴ ∠ABD = 90° - ∠DAB = 90° - 65° = 25°
AB || DC
∴ ∠BDC = ∠ABD = 25° (Alternate angles)
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