ABCD is a square E and F are respectively the mid point of BC and CD in R is a mid point of EF prove that area of ∆AER = area of ∆AFR
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draw AN perpendicular to EF
triangle AER = 1/2×base×height
=1/2×ER×AN
1/2×FR×AN. {R is the mid point of EF so ER = FR}
=area of triangle AFR
triangle AER = 1/2×base×height
=1/2×ER×AN
1/2×FR×AN. {R is the mid point of EF so ER = FR}
=area of triangle AFR
Akanshasrivastava:
thnq
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