ABCD is a square. find the measure of angle DAC and angle DCA
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WE know in a square every angle is equal to 90°.
Now in ∆ACD,
AD = CD ( all sides of a square are equal)
We know angle opposite to equal sides are equl so ∠1=∠2=x (say)
We know sum of all angles of a triangle is equal to 180°
∠1+∠2+∠D = 180°
x+x+90°=180°
2x=90°
x= 45°
So ∠1=∠2=45°
∠1=∠DAC =∠DCA=45°
Now in ∆ACD,
AD = CD ( all sides of a square are equal)
We know angle opposite to equal sides are equl so ∠1=∠2=x (say)
We know sum of all angles of a triangle is equal to 180°
∠1+∠2+∠D = 180°
x+x+90°=180°
2x=90°
x= 45°
So ∠1=∠2=45°
∠1=∠DAC =∠DCA=45°
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Swarup1998:
Draw figures in note books. They look better. Nice answer.
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ABCD is a square. find the measure of angle DAC and angle DCA
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