Question

ABCD is a square. Fs the mid-pont of AB and Esa punt on 8C such mat Beis one-third of BC if area of AFBE = 108 mir the length of AC =9K/2m
then K=?​

Answer 1

Answer:

Given that,

AF=FB=1/2AB

BE=1/2BC

Area of BFE=1/2×BF×BE

147=1/2×(1/2AB)×(1/3BC)

147=1/2×1/2×1/3×(AB)2[∵AB=BC]

(AB)^2=1764

AB=42m

We know that,

AC= diagonal of square =side√2=AB√2

=42√2m.