ABCD is a square. M is the mid-point of AB. E is a point on AD.EM produced meets
CB produced at F. If AB = 5 cm and EA = 1 cm, then find CF.
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Answer:
ΔPAMandΔBMQ
∠PMA=∠BMQ=α
AM=MB
∠PAM=∠MBQ=90
∘
InΔCPQ
LM⊥PQ
PM=MQ
CP=CQ(isoscelesΔCPQ)
CQ=CB+BQ
CQ=AB+BQ
So,BA=BQ
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