ABCD is a square
M the mid point of AB and PQ perpendicular to CM meets AD at P and CV produced to Q
PLEASE HELP ME FIND CP=AB+PA
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in triangle PCM and QCM
PM = QM
CM = CM
angle CMP = angle QMC
so both triangles are concurrent
CP = CQ
CP = BC + BQ
CP = AB + AP ( AB = BX , BQ= AP)
PM = QM
CM = CM
angle CMP = angle QMC
so both triangles are concurrent
CP = CQ
CP = BC + BQ
CP = AB + AP ( AB = BX , BQ= AP)
aryapallathil:
Thanks a lot
you are welcome
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