Sum of the digits of a two-digit number is 9. When we interchange the digits, it is found that the resulting new number is greater than the original number by 27. What is the two-digit number ?
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Answered by
22
let a & b be the digits of the no.
given,
(10b+a)-(10a+b)=27
9b-9a=27
b-a=3
a+b=9(given)
then 2b=12
b=6
a=3
the no.=36
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please
given,
(10b+a)-(10a+b)=27
9b-9a=27
b-a=3
a+b=9(given)
then 2b=12
b=6
a=3
the no.=36
let me know if there's issue... don't report please!...
please
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Answered by
8
Let one of the digits be 'x'
The other digit is : 9-x
So the number is
Tens. Ones
10(9-x) x
90-10x. x
Number:90-10x+x
=90-9x
On interchanging the digits:
Tens. Ones
10x. 9-x
Number:10x+9-x
=9x+9
According to the question:
90-9x+27 = 9x+9
117-9x = 9x+9
-9x-9x = 9-117
-18x = -108
x = -108/-18
x = 6
9-x = 9-6
=3
So the origanal number is 36
The other digit is : 9-x
So the number is
Tens. Ones
10(9-x) x
90-10x. x
Number:90-10x+x
=90-9x
On interchanging the digits:
Tens. Ones
10x. 9-x
Number:10x+9-x
=9x+9
According to the question:
90-9x+27 = 9x+9
117-9x = 9x+9
-9x-9x = 9-117
-18x = -108
x = -108/-18
x = 6
9-x = 9-6
=3
So the origanal number is 36
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