ABCD is a square of 30 m long in the figure. Find the area of the shaded portion
Fig. 22.43
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Diameter of Semicircle = 30m
Area of square = side × side
= 30 × 30
= 900m square.
Area of 2 semicircle = 2× 22/7 × 15 × 15 / 2
= 717.14 m square
Area of shaded region = Ar. of square - Ar. of 2 semicircle.
= 900-707.14
=192.86m square
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