Question

ABCD is a square of side 24 cm. EF is parallel to BC and AE=15 cm by how much does (1) the perimeter of AEFD exceed the perimeter of EBCF? (2) the area of AEFD exceed the area of EBCF?

Answer 1

1))
in square ABCD
AB=BC=CD=DA=24CM
EF||BC
IN AEFD AE=15 = DF (BREADTH)
AD=24=EF (LENGTH)
PERIMETER OF AEFD=2 (L+B)
》2 (24+15)=2 (39)
》78 CM
》IN RECTANGLE EBCF
》EB=24-15=9=FC
》BC=EF=24
》PERIMETER = 2(L+B)
》2 (9+24)=2 (33)
》66CM
》PERIMETER OF AEFD EXCEEDS BY 78-66=12 CM

2))
》IN RECTABLE AEFD = AREA IS L×B=(24×15)
》L×B=360cm^2
》IN RECTANGLE EBCF= AREA IS L×B=(24×9)
》L×B=216CM^2
》AREA OF AEFD EXCEEDS BY 360-216=144cm^2

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Answer 2

ok hope u understand it well