Math, asked by khan121, 1 year ago

ABCD is a square of side 24 cm. EF is parallel to BC and AE=15 cm by how much does (1) the perimeter of AEFD exceed the perimeter of EBCF? (2) the area of AEFD exceed the area of EBCF?

Answers

Answered by RahulCR7
196
1))
in square ABCD
AB=BC=CD=DA=24CM
EF||BC
IN AEFD AE=15 = DF (BREADTH)
AD=24=EF (LENGTH)
PERIMETER OF AEFD=2 (L+B)
》2 (24+15)=2 (39)
》78 CM
》IN RECTANGLE EBCF
》EB=24-15=9=FC
》BC=EF=24
》PERIMETER = 2(L+B)
》2 (9+24)=2 (33)
》66CM
》PERIMETER OF AEFD EXCEEDS BY 78-66=12 CM

2))
》IN RECTABLE AEFD = AREA IS L×B=(24×15)
》L×B=360cm^2
》IN RECTANGLE EBCF= AREA IS L×B=(24×9)
》L×B=216CM^2
》AREA OF AEFD EXCEEDS BY 360-216=144cm^2

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Answered by bubblez59
11

ok hope u understand it well

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