Abcd is a square of side 4cm. a point p is on ad find the minimum possible lenght of bp and cp together (in cm).
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Root 20 is the length of bp nd cp
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so the longest side will be the diagonal
for BP to be maximum P should be on D similarly for CP max P should be on A
by Pythagoras theorm you can find the diagonal
CP=BP=4√2=4× 1.414=5.656
so together CP + BP =11.312
for BP to be maximum P should be on D similarly for CP max P should be on A
by Pythagoras theorm you can find the diagonal
CP=BP=4√2=4× 1.414=5.656
so together CP + BP =11.312
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