Question

ABCD is a square of side ‘x’ cm. PQRS is a rectangle of dimension ( x + 3 ) cm by
( x – 3 ) cm.
i) Show that ABCD and PQRS have equal perimeters.
ii) Find the area of PQRS.
iii) Which figure has the greater area ? How much more is the area in square
centimetres ?

Answer 1

Answer:

Step-by-step explanation:

1)perimeter of square =4x

Perimeter of rectangle =2(l+b)=2(x+3+x-3)=4x

Hence perimeters are equal

2)area of rectangle =length×breadth

=(x+3)×(x-3)=x^2-9

3)from 2 area of rectangle is (x^2-9)

Area of square =a^2=x^2

X^2>(x^2-9)

Therefore area of square is more