Question

Abcd is a square.P and q are points on dc and bc respectively such that ap=dq.Prove that 1.Triangle adp= triangle dcq 2.Angle dmp=90

Answer 1

Given DQ = AP

ABCD is a square.

To Find ∠DRP

In triangle APB and AQD

AP = DQ (given)

AB = AD (side of square)

R. H. S rule

Triangle ABP Triangle ADR

Hence

x = ∠ADQ = ∠PAB and

∠APB =∠AQD= y

Now

x + y = 900

In triangle APQ,

∠ARQ = 90 = 1800 (x + y) = 180 – 90 = 90

Answer 2

Answer:

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Step-by-step explanation:

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