abcd is a square with ab= 15cm gind the area of the square of bfde.
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28
hi friend,
given AB=15cm
in abcd BD is the diagonal
now ,BCD is a right angled triangle..
BC ²+CD ²=BD²
15²+15²=BD²
225+225=BD²
450=BD²
now ,area of square bdfe is square of any side of square bdfe
→BD²=450 cm²
I hope this will help u ;)
given AB=15cm
in abcd BD is the diagonal
now ,BCD is a right angled triangle..
BC ²+CD ²=BD²
15²+15²=BD²
225+225=BD²
450=BD²
now ,area of square bdfe is square of any side of square bdfe
→BD²=450 cm²
I hope this will help u ;)
Answered by
5
In Square ABCD,
Diagonal BD=√2 a=√2 * 15=21.21 cm
Since BD is a side of Square BDFE
Therefore area of BDFE=a^2=(21.21)^2=449.86 cm^2
Diagonal BD=√2 a=√2 * 15=21.21 cm
Since BD is a side of Square BDFE
Therefore area of BDFE=a^2=(21.21)^2=449.86 cm^2
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