The expression 2x4-5x2+ax+b has a
factor(x+2) and leaves remainder of 6 when divided b x-1 Calculate
the value of a and b.
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The expression 2x⁴-5x²+ax+b has a factor (x+2)
x+2=0
⇒x=-2
Put x=-2 in given expression,
2(-2)⁴-5(-2)²+a(-2)+b=0
2(16)-5(4)-2a+b=0
32-20-2a+b=0
12-2a+b=0
-2a+b=-12--------(1)
The expression leaves remainder 6 when divided by x+1
x+1=0
⇒x=-1
2(-1)⁴-5(-1)²+a(-1)+b=6
2(1)-5(1)-a+b=6
2-5-a+b=6
-a+b=6-2+5
-a+b=9------(2)
(1)-(2)
-2a+b-(-a+b)=-12-9
-2a+b+a-b=-21
-a=-21
a=21
Put a=21 in (2)
-a+b=9
-21+b=9
b=30
Therefore,a=21 and b=30
Hope it helps
x+2=0
⇒x=-2
Put x=-2 in given expression,
2(-2)⁴-5(-2)²+a(-2)+b=0
2(16)-5(4)-2a+b=0
32-20-2a+b=0
12-2a+b=0
-2a+b=-12--------(1)
The expression leaves remainder 6 when divided by x+1
x+1=0
⇒x=-1
2(-1)⁴-5(-1)²+a(-1)+b=6
2(1)-5(1)-a+b=6
2-5-a+b=6
-a+b=6-2+5
-a+b=9------(2)
(1)-(2)
-2a+b-(-a+b)=-12-9
-2a+b+a-b=-21
-a=-21
a=21
Put a=21 in (2)
-a+b=9
-21+b=9
b=30
Therefore,a=21 and b=30
Hope it helps
Aarohan1:
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