ABCD is a trapezium, ab||dc and F is the midpoint of AD. prove that (i) AB=DC (ii) CE =AB + CD
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Step-by-step explanation:
as ABCD a trapezium AB||CD so AB||CE
IN ΔAFE and ΔEFD
AF = FD (F MID OF AD)
angAFB = angEFD(VOA)
angEFD = angFAB(AIA)
SO ΔAFE ≅ ΔEFD
AB=ED
AS CE=CD+DE
SO CE=AB+CD(AS AB=ED)
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