ABCD IS A TRAPEZIUM AB PARALLEL CD THEMAIL AB = 25 CD = 11 AD = 15 AND BC =13 FIND AREA OF TRAPEZIUM
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Answered by
1
area of trapezium=1/2(a+b)h(a and b refers to parallel sides and h refers to height)
=1/2(25+11)13
=1/2*36*13
=18*13
=234
hence area=234
=1/2(25+11)13
=1/2*36*13
=18*13
=234
hence area=234
pragyakapoor1:
this is not right answer
Answered by
0
firstly we will find the distance b/w two parallel lines by Pytha th DK= √29
area of trapezium = 1/2(AB+CD)×h
=1/2(25+11)×√29
=18√29
area of trapezium = 1/2(AB+CD)×h
=1/2(25+11)×√29
=18√29
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