Question

ABCD is a trapezium in which AB = 7 cm , AD = BC = 5 cm , DC = x cm , and distance between AB and DC is 4 cm . Find the value of x and area of trapezium ABCD​

Answer 1

Answer:

2(x+5) cm²

Step-by-step explanation:

If distance between two lines are given, two lines are parallel(as they don't meet).

so AB//DC.

(AREA OF ABCD) = 1/2 * ( AB + DC ) * height

Height is the distance between AB and DC, so 4 cm.

AB + DC = ( x + 5 ) cm

∴$\frac{1}{2}\times 4 \times (x+5)=2(x+5)$ cm²