ABCD is a trapezium in which AB || DC and its
diagonals intensa cachher at the point o Show
with figure
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Answered by
1
Answer:
Given:ABCD is a Trapezium
AB||CD
To Prove: AB=CD
Proof: In ∆ ABC and ∆ ABD
BA=BC (Given)
AB=AB( Common side)
∆ABC=∆ABD
AB=AB( CPCT)
ABCD is a Trapezium
Answered by
1
ANSWER
In trapezium ABCD, the diagonals intersect each other at O. In triangle OAB and OCD
∠AOB=∠COD (opposite angles)
∠ABO=∠ODC (alternate angles on parallel lines)
∠BAO=∠OCD (alternate angles on parallel lines)
Therefore, triangle OAB and OCD are similar.
Hence
OB
OA
=
OD
OC
or
OC
OA
=
OD
OB
In trapezium ABCD, the diagonals intersect each other at O. In triangle OAB and OCD
∠AOB=∠COD (opposite angles)
∠ABO=∠ODC (alternate angles on parallel lines)
∠BAO=∠OCD (alternate angles on parallel lines)
Therefore, triangle OAB and OCD are similar.
Hence
OB
OA
=
OD
OC
or
OC
OA
=
OD
OB
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