Math, asked by sarojabaadkar3, 8 months ago

ABCD is a trapezium in which AB || DC and its
diagonals intensa cachher at the point o Show
with figure

Answers

Answered by mlhombli
1

Answer:

Given:ABCD is a Trapezium

AB||CD

To Prove: AB=CD

Proof: In ∆ ABC and ∆ ABD

BA=BC (Given)

AB=AB( Common side)

∆ABC=∆ABD

AB=AB( CPCT)

ABCD is a Trapezium

Answered by Khansanaya439
1
ANSWER
In trapezium ABCD, the diagonals intersect each other at O. In triangle OAB and OCD
∠AOB=∠COD (opposite angles)
∠ABO=∠ODC (alternate angles on parallel lines)
∠BAO=∠OCD (alternate angles on parallel lines)
Therefore, triangle OAB and OCD are similar.
Hence
OB
OA

=
OD
OC


or
OC
OA

=
OD
OB

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