Question

ABCD IS A TRAPEZIUM IN WHICH AB||DC BD IS THE DIAGONAL AND E IS THE MIDPOINT OF AD. A LINE IS DRAWN THROUGH E PARALLEL AB INTERSECTING BC AT F .IF DC = 4CM AND AB=6CM THEN EF (DRAW THE FIGURE ALSO )​

Answer 1

Answer:

Given ABCD is a trapezium.

We have to prove, F is the mid point of BC, i.e., BF=CF

Let EF intersect DB at G.

In ΔABD E is the mid point of AD and EG∣∣AB.

∴ G will be the mid-point of DB.

Now EF∣∣AB and AB∣∣CD

∴ EF∣∣CD

∴ In ΔBCD, GF∣∣CD

⇒ F is the mid point of BC.