ABCD is a trapezium in which AB is parallel to CD and AB =15cm,AD = 9cm, AC= 41cm and angle ADC = 90 degree. find the are of trapezium
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Answer:
375 cm^2
Step-by-step explanation:
We know that area of trapezium= 1/2×sum of parallel sides of trapezium× distance between them
1/2×15×50
=375cm^2
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