Question

ABCD is a trapezium in which ab is parallel to dc a b is equal to 78 CM CD is equal to 52 cm is equal to 28 cm and BC is equal to 30 cm find the area of the trapezium

Answer 1

hey there !!

we know that area of trapezium = 1/2(sum of || sides) × height of trapezium

so firstly we ha e to find out the height of trapezium .

firstly we have to draw a perpendicular Ax at cd from the vertex A of the trapezium.

than we got a right angle triangle .

so , base of the triangle CX = ( ab - CD )

base of ∆ = 78-52 = 26cm

now,

in right triangle ∆AXC by Pythagoras theorem we get ax

Ax² = Ac² - cx²

Ax² = 30² - 26²

ax² = 900-676

ax² = 224

ax = 14.96

so we get the height of trapezium is 14.96

now ,

area of trapezium = 1/2(78+52)×14.96

area of trapezium = 1944.8/2 = 972.4sq. units.

hope it helps ,,

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Answer 2

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