Math, asked by Madhur00193, 4 months ago

ABCD is a trapezium in which AB is parallel to DC and AD = BC . If CE is drawn parallel to AD meeting AB at E , prove the following -
a- AECD is a parallelogram
b- AD=EC
c- triangle CEB is an isosceles triangle​

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Answered by vikhesham61gmailcom
1

Answer:

Show that ∠ A = ∠ B [Hint: Extend AB and draw a line through C parallel to DA ... at E. Given: ABCD is a trapezium where AB ∥ CD and AD = BC To prove:

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