Question

ABCD is a trapezium in which AB parallel to CD.if angle A= angle B=40 degree , what are the measure of the other two angles

Answer 1

If
$a = b = 40$
$a = 40 = b = 40$
$a + b = 80$
$a + b + c + d = 360$
$80 + c + d = 360$
$c + d = 360 - 80$
$c + d = 280$
$c = \frac{280}{2}$
$c = 140$
$c = d$
$d = 140$

Answer 2

Answer:

C= 140°

D= 140°

Step-by-step explanation:

A=B=40°

A+B+C+D=360° (angle sum property)

40+40+C+D=360°

80+C+D=360°

C+D= 360-80

      =280

C= $\frac{280}{2}$ = 140°

C=D

D=140°

Hope This ans helped!!!