Abcd is a trapezium in which ab parallel to dc and ab=2cd
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Question
- In a trapezium ABCD with AB║DC diagonals intersect each other at the point 'O'. If 2AB = 2CD, find the ratio of areas of triangles AOB and COD.
Answer:
- 4 : 1 is the required ratio
Step-by-step explanation:
Given
- In a trapezium ABCD
- AB║DC
- AB = 2CD
To find
- ar(ΔAOB) : ar(ΔCOD)
Solution
(In ΔAOB and ΔCOD)
- ∠AOB = ∠COD (vertically opposite angles)
- ∠BOA = ∠DCO (alternate interior angles)
- ΔAOB ~ ΔCOD
(By AA similarity)
- ar(ΔAOB)/ar(ΔCOD) = AB²/DC²
- (2DC)²/(DC)² = 4/1
∴ ar(ΔAOB) : ar(ΔCOD) = 4 : 1
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