Question

ABCD is a trapezium in which AB parralel DC. if angle A =60° and angle B = 40°. find the measures of its remaining two angles​

Answer 1

Answer:

remaining two angles are 120°,140°

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Answer 2

Answer:

ABCD is a trapezium in which AB parallels DC. if angle A =60° and angle B = 40°, then the measures of its remaining two angles​ are ∠C=140° and  ∠D=120°.

Step-by-step explanation:

ABCD is a trapezium in which  

AB ∥ DC

∠A=60°

∠B=40°          

AB∥DC an AD is a transversal line.

∴  ∠A+∠D=180°  

⇒  60° +∠D=180°  

⇒  ∠D=180° - 60°  

∴  ∠D=120°  

AB∥DC an BC is a transversal line.

∴  ∠B+∠C=180°

⇒  40° +∠C=180°  

⇒ ∠C=180°-40°

∴  ∠C=140°

So, the remaining two angles are ∠C=140° and  ∠D=120°  .