ABCD is a trapezium in which ad parallel to bc and ad=bc and o is the mid point of cd then show that ar(aob)=half ar(abcd).
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we know,
Triangle and a parallelogram on same base and between the same parallel,then area of triangle is half of parallelogram.
Therefore, ar(AOB) = ar(//gm ABCD)
Triangle and a parallelogram on same base and between the same parallel,then area of triangle is half of parallelogram.
Therefore, ar(AOB) = ar(//gm ABCD)
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