Question

Abcd is a trapezium in which side ABllcd. E is the mid point of side ad if f is the point on side bc such that segment efllcd prove that f is the mid point of bc and ef=1/2 (ab+cd)

Answer 1

We join A to C. Let AC intersect EF at G, then
In triangle ADC,
E is the mid point of AD and EG//CD,
Therefore, G is the mid point of AC and EG is equal to half of CD.
similarly in triangle CAB, GF =1/2AB and F is the mid point of BC.

Answer 2

Answer:

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