ABCD is a trapezium l AE = 12 cm. side AD = side BC. line AD = 15 cm. then find the area of the trapezium.
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Apply Pythagoras theorem in Triangles BFC and ADE. Get the base 5 (√(13^2+12^2)) for triangle ADE and for triangle BFC also base is 5 (√(13^2+12^2)). Then AB=EF then EF=15 Therefore find the area 1/2(sum of || sides * height).
1/2(15+20)*12=35*6= 210 sq. units
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Answer:
240
Step-by-step explanation:
1/2 ×(a+b) × h
1/2 ×(25 + 15 ) ×12
40×6
240
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