Question

ABCD is a trapezium of 91 cm square CD is parallel to ab and CD is longer than a b by 8 cm if the distance between a b and CD is 7 cm find a b and CD

Answer 1

hello friend
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____Here is your answer____
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CD = AB + 8
AB = CD - 8

area of trapezium
$= \frac{1}{2} \times h \times (sum \: of \: parallel \: sides)$
$91 = \frac{1}{2} \times 7 \times (ab \: + cd)$
$91 \times \frac{2}{7} = (cd + cd - 8)$
$26 = 2cd - 8$
so,
$cd = \frac{26 + 8}{2}$
CD = 17 cm
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